In trapezium $A B C D$ , the length of the parallel sides are $8 c m$ and $6 c m$ . if the distance between those parallel sides is $4 c m$ , then the area of the trapezium is

48 s q c m

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24 s q c m

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28 s q c m

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56 s q c m

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Solution

The correct option is C $28 s q c m$
Area $= \frac{1}{2}$ (Sum of parallel sides) $\times h$
$= \frac{1}{2} \times (8 + 6) \times 4 = 28 c m^{2}$

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In trapezium ABCD, the length of the parallel sides are 8 cm and 6 cm. if the distance between those parallel sides is 4cm, then the area of the trapezium is

The correct option is C 28 sq cmArea =12(Sum of parallel sides)×h=12×(8+6)×4=28cm2

In trapezium $A B C D$ , the length of the parallel sides are $8 c m$ and $6 c m$ . if the distance between those parallel sides is $4 c m$ , then the area of the trapezium is

The correct option is C $28 s q c m$
Area $= \frac{1}{2}$ (Sum of parallel sides) $\times h$
$= \frac{1}{2} \times (8 + 6) \times 4 = 28 c m^{2}$