Question

In trapezium ABED, C is the mid point of BE, ABCD is a rectangle with AB = 40 cm, BC = 20 cm. Find the area of trapezium ABED.

• A. 1200 ${\text{cm}}^2$
• B. 800 ${\text{cm}}^2$
• C. 400 ${\text{cm}}^2$
• D. 1600 ${\text{cm}}^2$

Answer 1

The correct option is A 1200 ${\text{cm}}^2$

From figure,
ABCD is a rectangle and DCE is a right angled triangle
Area of rectangle = l x b
=20 x 40
=800 ${\text{cm}}^2$...(i)
Area of $\Delta$ DCE = $\frac{1}{2}\times base\times height$
= $\frac{1}{2}\times 40\times 20$
=400 ${\text{cm}}^2$...(ii)
$\therefore$Area of trapezium ABED
= Area of rectangle ABCD + Area of $\Delta$DCE
=400 + 800
=1200 ${\text{cm}}^2$