Question

In triangle ABC, a =2, b =3 and sin $A=\frac{2}{3},$ then B is equal to

• A. 30°
• B. 60°
• C. 90°
• D. 120°

Answer 1

The correct option is C

90°

$\text{Using sine rule,}\frac{sinA}{a}=\frac{sinB}{b}\Rightarrow \frac{2/3}{2}=\frac{sinB}{3}\Rightarrow sinB=1\Rightarrow B={90}^0$