In triangle ABC,a2+c2=2002b2, then cotA + cotCcotB is equal to
12001
22001
32001
42001
cotA + cotCcotB=cosAsinA + cosCsinCcosBsinB=sin(A+C)sinBsinAcosBsinC=sin2BsinAcosBsinC=4R2b24R2accosB=2b22accosB=2b2a2+c2−b2=2b22002b2−b2=22001
In a triangle ABC, 2ca sinA−B+C2 is equal to
In a △ABC,2casin(A−B+C2) is equal to