Question

In $△$ABC, AB = 3 and, AC = 4 cm and AD is the bisector of $\angle$A. Then, BD : DC is —

• A. 9:16
• B. 16:9
• C. 3:4
• D. 4:3

Answer 1

The correct option is C

3:4

According to angle bisector theorem, the internal bisector of an angle of a triangle divided the oppposite side internally in the ratio of the corresponding sides containing the angle.

In $△ABC$

as per the statement $\frac{AB}{AC}=\frac{BD}{DC}$ i.e. $\frac{a}{b}=\frac{c}{d}$

So, $\frac{BD}{DC}$ = $\frac{AB}{AC}$ =$\frac{3}{4}$

So, BD : DC = 3 : 4