In ABC - AB -3 and- AC -4 cm and AD is the bisector of - A- Then- BD - DC is -A- 4- 3B- 16- 9C- 3- 4D- 9- 16

The correct option is C 3:4 BD/DC = AB/AC =3/4 So, BD : DC = 3 : 4. ...

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Basic proportionality theorem

In ABC , AB =...

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In $△$ ABC, AB = 3 and, AC = 4 cm and AD is the bisector of $∠$ A. Then, BD : DC is —

9:16

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16:9

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3:4

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4:3

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In $△$ ABC, AB = 3 cm, AC = 4 cm and AD is the bisector of $∠$ A. Then, BD : DC is —

In $△ A B C, A B = 3 c m, A C = 4 c m$ and AD is the bisector of $∠$ A. Then, $B D : D C$ is

△ A B C

A B = 3 c m, A C = 4 c m

A D

∠ A

B D : D C

\sqrt{3} : 2

△ A B C, A B = 3 c m, A C = 4 c m

∠

B D : D C

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