In $△ A B C, A B = 3 c m, A C = 4 c m$ and AD is the bisector of $∠$ A. Then, $B D : D C$ is
0.25

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Solution

The correct option is A 0.25

"Angle Bisector" Theorem says that an angle bisector of a triangle will divide the opposite side into two segments that are proportional to the other two sides of the triangle.

$\frac{B D}{D C} = \frac{A B}{A C} = \frac{3}{4}$

So, $B D : D C = 3 : 4 = 0.25$

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