In ABC - AB -3 cm - AC -4 cm and AD is the bisector of - A- Then- BD - DC-A- TrueB- False

The correct option is B False Using angle bisector theorem, BD/DC =AB/AC =3/4 So, BD : DC = 3 : 4 Since, BD:DC 1:1 Hence, BD DC Thus, the given statemen ...

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Standard X

Mathematics

Internal Angle Bisector Theorem

In ABC , AB =...

Question

In $△ A B C, A B = 3 c m, A C = 4 c m$ and AD is the bisector of $∠$ A. Then, $B D = D C .$

True

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False

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Solution

The correct option is B
False

Using angle bisector theorem, $\frac{B D}{D C} = \frac{A B}{A C} = \frac{3}{4}$

So, $B D : D C = 3 : 4$

Since, $B D : D C \neq 1 : 1$

Hence, $B D \neq D C$

Thus, the given statement is False

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Q. In a Δ ABC, AD is the bisector of ∠A, meeting side BC at D. If BD = 2.5 cm, AB = 5 cm, and AC = 4.2 cm, find DC.

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In △ABC, AB=3 cm, AC=4 cm and AD is the bisector of ∠A. Then, BD=DC.

The correct option is B False ​​ Using angle bisector theorem, BDDC=ABAC=34 So, BD:DC=3:4 Since, BD:DC≠1:1 Hence, BD≠DC Thus, the given statement is False

In $△ A B C, A B = 3 c m, A C = 4 c m$ and AD is the bisector of $∠$ A. Then, $B D = D C .$

The correct option is B
False

Using angle bisector theorem, $\frac{B D}{D C} = \frac{A B}{A C} = \frac{3}{4}$

So, $B D : D C = 3 : 4$

Since, $B D : D C \neq 1 : 1$

Hence, $B D \neq D C$

Thus, the given statement is False