In ABC - AB -3 cm - AC -4 cm and AD is the bisector of - A- Then- BD - DC isA- 9- 16B- 4- 3C- 16- 9D- 3- 4

The correct option is D 3:4 Using angle bisector theorem, BD/DC =AB/AC =3/4 So, BD : DC = 3 : 4. ...

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Internal Angle Bisector Theorem

In ABC , AB =...

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In $△ A B C, A B = 3 c m, A C = 4 c m$ and AD is the bisector of $∠$ A. Then, $B D : D C$ is

9:16

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16:9

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3:4

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4:3

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In $△$ ABC, AB = 3 cm, AC = 4 cm and AD is the bisector of $∠$ A. Then, BD : DC is —

△ A B C, A B = 3 c m, A C = 4 c m

∠

B D : D C

△ A B C

A B = 3 c m, A C = 4 c m

A D

∠ A

B D : D C

In $△$ ABC, AB = 3 and, AC = 4 cm and AD is the bisector of $∠$ A. Then, BD : DC is —

△ A B C, A B = 3 c m, A C = 4 c m

∠

B D : D C

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