In triangle ABC, AB=5, BC=12, AC=13, ∠ACB=x and ∠ABC=90∘. If the value of sinx+secx+tanx is a, then 156a=
For angle x in the right-angled triangle,
sinx=Opposite sideHypotenuse
secx=HypotenuseOpposite side=1cosx
tanx=Opposite sideAdjacent side
From this triangle, we get
sinx=513
secx=1312
tanx=512
⇒sinx+secx+tanx=513+1312+512
⇒a=294156
⇒156a=294