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Area of a Triangle

In ABC, A...

Question

In $△ A B C$ , $A B = 5$ cm, $B C = 5.5$ cm, $A C = 7.5$ cm. Find the perimeter of the $△$ formed by joining the midpoints of $A B, B C$ and $A C$ .

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Solution

$T r i a n g l e f o r m e d b y j o i n i n g m i d - p o i n t s w i l l h a v e s i d e l e n g t h h a l f o f t h e o r i g i n a l t r i a n g l e a n d h e n c e h a l f o f t h e o r i g i n a l p e r i m e t e r l e n g t h ∴ r e q u i r e d p e r i m e t e r = (\frac{5 + 5.5 + 7.5}{2}) = 9 c m$

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