In $△ A B C, A B = 6 c m, B C = 7 c m$ and $∠ A = 60^{o}$

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Solution

First take AB
Then take AC
Take BC
Cross point is B
Complete the triangle
Find perpendicular bisector of AB and AC
Their intersection is at a point D
Now draw a circle taking DA as radius

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△ A B C, A B = 6 c m, B C = 7 c m

∠ A = 60^{o}

△ A B C, A B = 6 c m, B C = 7 c m

∠ A = 60^{o}

A B C

B C = 6 c m

A B = 9 c m

A B C = 60^{o}

△ A B C, A B = 6 c m, B C = 7 c m

A C = 5 c m

△ A B C

Δ A B C

A B = 5 c m, A C = 7 c m, B C = 6 c m

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