Question

In $△ABC$,$AB=AC$ and $AD$ is the perpendicular bisector of $BC$. Show that $△ADB\cong △ADC$

Answer 1

R.E.F image

Given : $AD$ is the perpendicular

bisector of $BC,AB=AC$

To show $△ADB\cong △ADC$

proof :- In $△ADB$ and$△ADC$

$AD=AD$ (common)

$\angle ADB=\angle ADC$

$BD=CD$ ($AD$ is perpendicular bisector)

$\therefore △ADB\cong △$ ADC by SAS congruence .