In $△ A B C$ , $A B = A C$ and $∠ B = 40^{\circ}$ . What type of triangle is this ?

6m, equilateral triangle

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4 m, Isosceles triangle

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6 m, Isosceles triangle

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4 m, equilateral triangle

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Solution

The correct options are
A
6m, equilateral triangle

B
4 m, Isosceles triangle

Since AB = AC, the angles opposite these sides will also be equal.
As AB = AC it is an isosceles triangle.

Hence, $∠ B = ∠ C$

$\Rightarrow ∠ C = 40^{\circ}$

$∠ A = 180^{\circ} - (∠ B + ∠ C)$

$∠ A = 180^{\circ} - 80^{\circ}$

$∠ A = 100^{\circ}$

Therefore, this is an obtuse angled triangle.

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