Question

In $△ABC$, AB=AC and $\angle B={50}^0$. Then $\angle C$ is equal to

• A. ${40}^0$
• B. ${50}^0$
• C. ${80}^0$
• D. ${130}^0$

Answer 1

Answer: (B)

${50}^0$

Given: $AB=AC$, $\angle B={50}^{\circ }$
Since, $AB=AC$
$\angle B=\angle C={50}^{\circ }$ (Angles opposite to equal sides are equal)