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Question

In ABC, AB=AC; BEAC and CFAB. Prove that :BE=CF.

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Solution

In ABC, AB=AC
So, B=C ....(i) (angles opposite to equal sides are equal)
In BEC and BFC,
E=F=90o (given)
BC=BC (common)
ABC=ACB (From (i))
Thus, BECBFC (AAS congruency)
Hence, BE=CF.

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