Question

In $△ABC$, $AB=BC=5cm$ and $\angle A={55}^0$, find $\angle B$.

• A. ${70}^0$
• B. ${62.5}^{\circ }$
• C. ${55}^{\circ }$
• D. ${50}^{\circ }$

Answer 1

The correct option is A ${70}^0$

In $△ABC$, $AB=AC$, $\angle A={55}^{\circ }$
Since, $AB=BC$
$\angle C=\angle A=55$
Sum of angles = 180
$\angle A+\angle B+\angle C=180$
$55+\angle B+55=180$
$\angle B={70}^{\circ }$.