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In triangle A...

Question

In triangle ABC, AD is the bisector of angle A, meeting BC at D, if BD = 2.5 cm, AB = 5cm and AC = 4.2 cm then DC

A

2.1 cm

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B

2.4 cm

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C

3.4 cm

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D

3.2 cm

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Solution

The correct option is A
2.1 cm

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Similar questions

Q. In a Δ ABC, AD is the bisector of ∠A, meeting side BC at D. If BD = 2.5 cm, AB = 5 cm, and AC = 4.2 cm, find DC.

Δ A B C, A D

is the bisector of

∠ A,

B C

D

B D = 2.5 c m, A B = 5 c m

A C = 4.2 c m

D C

△ A B C

, the internal bisector

A D

∠ A

B C

D

B D = 2.5 c m, A B = 5 c m

A C = 4.2 c m

D C

Q. If a ∆ ABC, AD is the bisector of ∠A, meeting side BC at D.

(i) If BD = 2.5 cm, AB = 5 cm and AC = 4.2 cm, find DC.
(ii) If BD = 2 cm, AB = 5 cm and DC = 3 cm, find AC.
(iii) If AB = 3.5 cm, AC = 4.2 cm and DC = 2.8 cm, find BD.
(iv) If AB = 10 cm, AC = 14 cm and BC = 6 cm, find BD and DC.
(v) If AC = 4.2 cm, DC = 6 cm and BC = 10 cm. find AB.
(vi) If AB = 5.6 cm, AC = 6 cm and DC = 3 cm, find BC.
(vii) If AD = 5.6 cm, BC = 6 cm and BD = 3.2 cm, find AC.
(viii) If AB = 10 cm, AC = 6 cm and BC = 12 cm, find BD and DC.

A D

is the internal bisector of

∠ A

A B C

B C

D

B D = 5 c m, B C = 7.5 c m

A B : A C

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