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Byju's Answer

Standard VIII

Mathematics

Medians of a Triangle and the Drawing Method

In triangle A...

Question

In triangle ABC AD is the median, then which of the following is correct ?

BD = CD

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BD = 2CD

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AD = AC

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AB = BD

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Solution

The correct option is A BD = CD
We know that,
a median divides the side of a triangle into two segments or parts of equal length. Hence BD = DC.

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Similar questions

Q. ABC is a right angled triangle with

∠ C = 90^{\circ}

and

C D ⊥ A B

then prove that

\frac{{B C}^{2}}{{A C}^{2}} = \frac{B D}{A D}

Q. In

△ A B C

, if

A D

is the median, show that

A B^{2} + A C^{2} = 2 (A D^{2} + B D^{2})

Q. In a triangle ABC, if AD is the median, then show that

{A B}^{2} + {A C}^{2} = 2 ({A D}^{2} + {B D}^{2})

△ A B C

is iscoeles in which

A B = A C

, seg

B D

and seg

C E

are medians show that

B D = C E

In a right $△$ ABC, a perpendicular BD is drawn on to the largest side from the opposite vertex. Which of the following does not give the ratio of the areas of $△$ ABD and $△$ ACB?

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In triangle ABC AD is the median, then which of the following is correct ?

The correct option is A BD = CD We know that, a median divides the side of a triangle into two segments or parts of equal length. Hence BD = DC.

The correct option is A BD = CD
We know that,
a median divides the side of a triangle into two segments or parts of equal length. Hence BD = DC.