In ABC and PQR- - A - - Q and - B - - R- Which side of - PQR should be equal to side AB of - ABC so that the two triangles are congruent-

The correct option is A QR Given, ∠ A = ∠ Q , ∠ B = ∠ R Side AB lies between ∠ A and ∠ B #160;and side QR lies between ...

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Standard X

Mathematics

SSS Similarity

In ABC and ...

Question

In $△ A B C$ and $△ P Q R$ , $∠ A = ∠ Q$ and $∠ B = ∠ R .$ Which side of $Δ$ $P Q R$ should be equal to side $A B$ of $Δ A B C$ so that the two triangles are congruent?

Q R

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P Q

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P R

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Any side of

△ P Q R

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Solution

The correct option is A $Q R$
Given, $∠ A = ∠ Q$ , $∠ B = ∠ R$
Side $A B$ lies between $∠ A$ and $∠ B$ and side $Q R$ lies between $∠ Q$ and $∠ R .$
Hence, $A B$ should be equal to $Q R$ as they are the corresponding sides.
The two triangles to be congruent by $A S A$ rule.

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Similar questions

Q. In

△ A B C

and

△ P Q R

∠ A = ∠ Q

and

∠ B = ∠ R .

Which side of

△ P Q R

should be equal to side

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△ A B C

so that the two triangles are congruent?

Q. In triangles

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and

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Q. In

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. which side of a

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, so that the two triangles are congruent? Give reason for your answer.

Q. In

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and

Δ P Q R, ∠ A = ∠ Q

and

∠ B = ∠ R

which side of

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Q. Question 1
In

Δ A B C

and

Δ P Q R

∠ A = ∠ Q

and

∠ B = ∠ R

. which side of a

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In △ABC and △PQR, ∠A=∠Q and ∠B=∠R. Which side of Δ PQR should be equal to side AB of ΔABC so that the two triangles are congruent?

The correct option is A QRGiven, ∠A=∠Q, ∠B=∠RSide AB lies between ∠A and ∠B and side QR lies between ∠Q and ∠R.Hence, AB should be equal to QR as they are the corresponding sides.The two triangles to be congruent by ASA rule.

In $△ A B C$ and $△ P Q R$ , $∠ A = ∠ Q$ and $∠ B = ∠ R .$ Which side of $Δ$ $P Q R$ should be equal to side $A B$ of $Δ A B C$ so that the two triangles are congruent?

The correct option is A $Q R$
Given, $∠ A = ∠ Q$ , $∠ B = ∠ R$
Side $A B$ lies between $∠ A$ and $∠ B$ and side $Q R$ lies between $∠ Q$ and $∠ R .$
Hence, $A B$ should be equal to $Q R$ as they are the corresponding sides.
The two triangles to be congruent by $A S A$ rule.