In $△ A B C$ , $∠ A = 30^{\circ}, a = 8$ cm, then distance of orthocentre from vertex $A$ is equal to

4

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8

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8 \sqrt{3}

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4 \sqrt{3}

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Solution

The correct option is C $8 \sqrt{3}$ cm
Distance of orthocentre from vertex $A = 2 R cos A = \frac{a}{sin A} \cdot cos A = 8 cot 30^{\circ} = 8 \sqrt{3}$

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