Question

In $△ABC,\angle A={65}^0,\angle C={30}^0$. Which side of the triangle is the longest? Give reason for your answer.

Answer 1

Solution:-

In a triangle, sum of all the angle will be $180°$.

$\therefore \angle A+\angle B+\angle C=180°$

$\Rightarrow 65°+\angle B+30°=180°\{\because \angle A=65°\&\angle C=30°\left(Given\right)\}$

$\Rightarrow \angle B=180°-95°=85°$

As we know that the longest side of a triangle will be opposite of largest angle.

$\because \angle B$ is the greatest among $\angle A,\angle B\&\angle C$ of $△ABC$, therefore the longest side will be $AC$, i.e., oppsite of $\angle B$.