Question

In $△ABC$, $\angle A={90}^{\circ }$, side $AB=x$ cm, $AC=(x+5)$ cm and $Area=150c{m}^2$. Find the sides of the triangle.

• A. 12 cm, 20 cm and 25 cm
• B. 11 cm, 20 cm and 25 cm
• C. 17 cm, 20 cm and 25 cm
• D. 15 cm, 20 cm and 25 cm

Answer 1

The correct option is D 15 cm, 20 cm and 25 cm

Area of the triangle $=\frac{1}{2}\times x\times (x+5)=150$
$=>x^2+5x-300=0$
$=>x=15cm$
The second side will be $x=15+5=20cm$
And, the hypotenuse will be $\sqrt{{15}^2+{20}^2}=25cm$