In ABC- -ABC - 90- AD - DC- AB -12 cm- BC - 6-5 cm- Find the area of ADB-

ADB = 12 ABC [ ∵ BD is a median of ABC] =12×[ 12× AB × AC ] = 14× 12 × 6.5 = 19.5 cm^2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

Identifying Figures on the Same Base and Between the Same Parallel Lines

In ABC, ∠ABC ...

Question

In $△$ ABC, $∠$ ABC $= 90^{\circ}$ ; AD = DC; AB =12 cm, BC = 6.5 cm. Find the area of $△$ ADB.

Open in App

Solution

$△ A D B = \frac{1}{2} △ A B C [∵ B D is a median of △ A B C]$
$= \frac{1}{2} \times [\frac{1}{2} \times A B \times A C]$
$= \frac{1}{4} \times 12 \times 6.5$
$= 19.5 {cm}^{2}$

Suggest Corrections

Similar questions

Q. In

△ A B C, ∠ A B C = 90^{o}, A D = D C, A B = 12 c m

and

B C = 6.5 c m

. Find the area of

△ A D B

In ΔABC, $∠ A B C = 90^{\circ}$ AD = DC, AB = 12 cm and BC =6.5 cm. Find the area of $△ A D B$ .

Q. In fig,

∠ A B C = 90^{o}, A C = B C, O A = 12 c m

and

O C = 6.5 c m

. Find the area of

△ A O B .

Q. Find the area of

△ A B C,

in which

A B = 4

cm,

B C = 5

cm and

∠ A = 90^{\circ}

$△ A B C$ is right-angled at $A . A D$ is perpendicular to $B C, A B = 5 c m, B C = 13 c m$ and $A C = 12 c m$ . Find the area of $△ A B C$ . Also, find the length of $A D$ .

Join BYJU'S Learning Program

In △ABC, ∠ABC =90∘; AD = DC; AB =12 cm, BC = 6.5 cm. Find the area of △ADB.

△ADB=12△ABC [∵BD is a median of △ABC] =12×[12×AB×AC] =14×12×6.5 =19.5 cm2

In $△$ ABC, $∠$ ABC $= 90^{\circ}$ ; AD = DC; AB =12 cm, BC = 6.5 cm. Find the area of $△$ ADB.

$△ A D B = \frac{1}{2} △ A B C [∵ B D is a median of △ A B C]$
$= \frac{1}{2} \times [\frac{1}{2} \times A B \times A C]$
$= \frac{1}{4} \times 12 \times 6.5$
$= 19.5 {cm}^{2}$