In triangle $A B C, ∠ B = 3 ∠ A - 25^{o}$ and $∠ A = ∠ C$ . Find angle B.

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Solution

$∠ B = 3 ∠ A - 25$
$∠ A = ∠ C$
Sum of angles of triangle = 180
$∠ A + ∠ B + ∠ C = 180$
$∠ A + 3 ∠ A - 25 + ∠ A = 180$
$5 ∠ A = 180 + 25$
$∠ A = 41^{\circ}$
$∠ B = 3 ∠ A - 25 = 3 \times 41 - 25 = 98^{\circ}$

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