In triangle ABC, angle B = 35o, angle C = 65o and the bisector of angle BAC meets BC in P. Choose the correct descending order of AP, BP and CP
CP > AP > BP
AP > CP > BP
BP > AP > CP
CP >AP > BP
In ΔABC, ∠B=35∘, ∠C=65∘ and the bisector of ∠BAC meets BC in P. Arrange AP, BP and CP in descending order.
BO and CO are respectively the bisectors of angle B and C of ∆ABC. AO produced meets BC at P. Show that AO/BP = AO/OP , AC/CP = AO/OP ,
AB/AC = BP/PC , AP is the bisector of angle BAC.
BO and CO are respectively the bisectors of ∠B and ∠C of ΔABC. AO produced meets BC at P. Show that [4 MARKS]
(i) ABBP=AOOP (ii) ACCP=AOOP (iii) ABAC=BPPC (iv) AP is the bisector of ∠BAC.