Question

In $△$ ABC, $\angle$B = ${90}^{\circ }$. If $cotA$ = $\sqrt{3}$ then, find the value of $cose{c}^{2}A$ - 1

• A. $\sqrt{3}$
• B. 3
• C. 1
• D. 9

Answer 1

The correct option is B 3

From Trigonometric Identity,
$cose{c}^{2}A-co{t}^{2}A=1$
$\Rightarrow$ $cose{c}^{2}A-1=co{t}^{2}A$ = $(\sqrt{3}{)}^2$ = 3
$\therefore$ $cose{c}^{2}A-1$ = 3