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Pythagoras Theorem

In ABC, ∠ B...

Question

In $△ A B C, ∠ B = 90^{o}, A B = 18 c m$ and $B C = 24 c m$ . Calculate the length of $A C$ .

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Solution

By Pythagoras Theorem, $A C^{2} = A B^{2} + B C^{2}$
$= 18^{2} + 24^{2}$
$= 324 + 576$
$= 900$
$∴ A C = \sqrt{900} = 30 c m$

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