In ABC- BAC-90- seg AD- seg BC and B -D-C- BD -3- DC -12 then find AD-

[ Use the geometric mean formula; for ur diagram is; AD× AD=BD× DC; =12× 3.; ...

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Van't Hoff Factor

In ABC,∠ BA...

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In $△ A B C, ∠ B A C = 90^{\circ},$ seg $A D ⊥$ seg $B C$ and $B - D - C, B D = 3, D C = 12$ then find $A D .$

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In a trapezium $A B C D$ , $A B ∥ D C$ , $B D ⊥ A D, A C ⊥ B C$ , If $A D = 15, B C = 15$ and $A B = 25$ . Find $A r (▢ A B C D)$

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= 15

= 15

= 25

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