In $△ A B C$ , $∠ C = 90^{o}$ . If $B C = a, A C = b$ and $A B = c$ , find $c$ when $a = 8 c m$ and $b = 6 c m$ .

10 c m

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14 c m

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15 c m

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20 c m

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Solution

The correct option is B $10 c m$
$∠ C = 90^{\circ}$ $B C = 8 c m$ $A C = 6 c m$

$A B^{2} = A C^{2} + B C^{2}$ .........(By Pythagoras theorem)
$A B^{2} = 8^{2} + 6^{2}$
$A B^{2} = 100$
$A B = 10 c m$

$c = 10 c m$

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In a $Δ A B C$ , AD is the bisector of $∠ A$ .

(i) If AB = 6.4 cm, AC = 8 cm and BD = 5.6 cm, find DC.

(ii) If AB = 10 cm, AC = 14 cm and BC = 6 cm, find BD and DC.

(iii) If AB = 5.6 cm, BD = 3.2 cm and BC = 6 cm, find AC.

(iv) If AB = 5.6 cm, AC = 4 cm and DC = 3 cm, find BC.

In a right triangle ABC, ∠B = 90°.

(a) If AB = 6 cm, BC = 8 cm, find AC

(b) If AC = 13 cm, BC = 5 cm, find AB

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