In triangle ABC, (b+c)cos A + (c+a) cos B + (a+b) cos C = [MP PET 1985]
A
1
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B
a + b + c
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C
2(a+b+c)
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Solution
The correct option is A 1 (b+c) cos A + (c + a)cos B + (a+b) cos C = a + b + c From expanding and collecting terms using projection rule, a = b cos C + c cos B etc.