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Angle between Pair of Straight Lines

In triangle A...

Question

In triangle ABC cosa/a=cosb/b=cosc/c the value of r1+r2+r3/r is equal to

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△ A B C, cos A + cos B + cos C = \frac{7}{4}

\frac{R}{r}

A B C

cos A + cos B + cos C = \frac{7}{4}

\frac{R}{r}

A B C

(cos A + cos B + cos C)

△ A B C

a < b < c

r

r_{1}, r_{2}, r_{3}

A, B, C

r < r_{1} < r_{2} < r_{3}

△ A B C, r_{1} r_{2} + r_{2} r_{3} + r_{3} r_{1} = \frac{r_{1} r_{2} r_{3}}{r}

\frac{cos A}{a} = \frac{cos B}{b} = \frac{cos C}{c}

△ A B C

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