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Question

In triangle ABC, D and E are the points on the sides AB and AC. DE||BC, BD=5 cm and DE:BC=2:3. Find AD and the ratio of are of triangle ADE to the quadrilateral BCED.

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Solution

DE||BC
ADEABC
AD/AB=DE/BC=AE/AC
DE/BC=2/3
AD/AB=2/3
AD/(AD+BD)=2/3
AD/(AD+2)=2/3
3AD=2AD+4
AD=4
And
Ratio of Area of Similar triangle = (Ratio of sides of similar triangle)2
Area of ADE / Area of ABC=(2/3)2

Area of ADE / Area of ABC=4/9

Area of ABC=9 Area of ADE/4

Area of quadrilateral bced = Area of ΔABC Area of ΔADE

Area of quadrilateral becd =9 Area of ADE/4 Area of ADE

Area of quadrilateral bced =5 Area of ADE/4

area of ADE/Area of quadrilateral bced =4/5


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