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Basic Proportionality Theorem and Its Forms

In triangle A...

Question

In triangle ABC, D and E are two points on AB and AC respectively. If AD : DB = 2 : 5 and DE || BC, then what is AE : EC ?

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Q. In ∆ABC, D and E are points on sides AB and AC respectively such that AD ✕ EC = AE ✕ DB. Prove that DE || BC.

Q. In triangle ABC, D and E are two points on AB an AC respectively. If AD : DB = AE : EC, then which is correct?

△

ABC, D and E are points on sides AB and AC respectively such that AD

\times

\times

DB. Prove that DE

∥

Q. In ∆ABC, D and E are points on sides AB and AC respectively such that AD ✕ EC = AE ✕ DB. Prove that DE || BC.

△ A B C

D

E

A B

A C

respectively such that

D E ∥ B C

A E = 2 c m, E C = 3 c m

B C = 10 c m

D E

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