Question

In triangle ABC, D is a point in AB such that AC =CD =DB. If $\angle$ B = ${28}^0$, find the angle ACD.

Answer 1

68 degree


in triangle BCD
CD=BD
so angle B=angle BCD = 28 degree

Angle ADC is ext opposite angle so
= 56 degree
in triangle ADC
AC = CD
so angle ADC = A = 56 degree

so angle ACD = 180- (56+56)
180- 112= 68 degree