In ABC- DE- BC and ADDB - 23- If AE - 3-7 cm- find EC

In ABC, DE∥ BC ∴ADDB = AEEC #160; ⇒ EC = AE× DBAD Thus, EC = 3.7× 32 = 5.55 cm ...

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Basic Proportionality Theorem

In ABC, DE∥...

Question

In $△ A B C, D E ∥ B C$ and $\frac{A D}{D B} = \frac{2}{3}$ . If $A E = 3.7 c m$ , find $E C$

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In a triangle ABC and DE parallel to BC , if AD= 1.5, AE=1cm and DB =3cm, find EC

Δ A B C, D E | | B C,

A D = x + 2, D B = 3 x + 16, A E = X a n d E C = 3 x + 5

Δ A B C

D E ∥ B C

A D

D B =

7.2

A E = 1.8

E C = 5.4

Δ A B C

D E ∥ B C

\frac{A D}{D B} = \frac{5}{4}

E C = 7.2

A E

△ A B C, D E ∥ B C

\frac{A D}{D B} = \frac{3}{5}

A C = 5.6

A E .

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