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Question

In ABC, cosecA2+cosecB2+cosecC2m Find m

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Solution

In ABC, we know that sinA2sinB2sinC218
cosecA2+cosecB2+cosecC23(cosecA2cosecB2cosecC2)1/3
cosecA2+cosecB2+cosecC231sinA2sinB2sinC21/3
cosecA2+cosecB2+cosecC23(8)1/3
cosecA2+cosecB2+cosecC26
Ans: m=6

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