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Question

In â–³ABCcos2A2a+cos2B2b+cos2C2c


A

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B

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C

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D

None of these

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Solution

The correct option is B


We have, cos2A2a+cos2B2b+cos2C2c
={s(s−a)bca}+{s(s−b)cab}+{s(s−c)abc}
=s(s−a+s−b+s−c)abc
=s[3s−(c+b+c)]abc
=s(3s−2s)abc=s2abc


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