In $△ A B C$ , if $∠ A = 45^{\circ}$ and $∠ B = 70^{\circ}$ , find the shortest and the largest sides of the triangle respectively

A B, B C

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B C, A C

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A B, A C

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Either (A) or (C)

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Solution

The correct option is A $B C, A C$
Given, $∠ A = 45^{0}$ and $∠ B = 70^{0}$
By angle sum property, $A + B + C = 180^{0}$
$⟹ 45 + 70 + C = 180$
$⟹ C = 65^{0}$
Angle opposite to longest side is larger and the side opposite to $∠ B$ is AC .
Also, shortest side is opposite to the shorter angle, $∠ A$ is BC.

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