Question

In $△ABC$, if $\angle B={76}^{\circ }$ and $\angle C={48}^{\circ }$, find $\angle A$ (in degrees).

Answer 1

We know that the sum of all the angles in a triangle is ${180}^{\circ }$.
So we can write it as
$\angle A+\angle B+\angle C={180}^{\circ }$
By substituting the values in the above equation we get
$\angle A+{76}^{\circ }+{48}^{\circ }={180}^{\circ }$
On further calculation
$\angle A={180}^{\circ }-{76}^{\circ }-{48}^{\circ }$
By subtraction we get
$\angle A={180}^{\circ }-{124}^{\circ }$
$\angle A={56}^{\circ }$
Therefore, the value of $\angle A$ is ${56}^{\circ }$.