In $△ A B C$ , if $b cos A = a cos B$ then the triangle is

right angled

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isosceless

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equilateral

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scalene

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Solution

The correct option is B isosceless
Given
In $△ A B C, b cos A = a cos B$
$2 R sin B cos A = 2 R sin A cos B$
$sin (B - A) = 0 ⟹ B = A$

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$c (a c o s B - b c o s A) = a^{2} - b^{2}$

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