In triangle ABC, if BC is base, angle B is 60°, AB-AC=0, what is the value of the angle opposite to side BC in degrees?
Sides AB and AC are equal since AB-AC=0. One angle is given to be 60°. An isosceles triangle with a 60° angle is an equilateral triangle. All of the 3 angles have a value 60°. Hence the required angle is 60° .