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Question

In triangle ABC, line joining the circumcentre and orthocentre is parallel to side AC then value of tanA,tanC is equal to

A
3
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B
3
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C
33
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D
none of these
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Solution

The correct option is B 3
Consider ABC where C is the circumcentre and O is the orthocentre.

Extend C and O to meet AC in E and F respectively.

We know that
CE=RcosB

OF=2RcosAcosC

CE=OF

RcosB=2RcosAcosC

cosB=2cosAcosC

cos(π(A+C))=2cosAcosC

cos(A+C)=2cosAcosC

(cosAcosCsinAsinC)=2cosAcosC

sinAsinC=3cosAcosC

tanAtanC=3

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