Question

In triangle ABC, line segment AB is congruent to line segment BC is congruent to line segment CA. Prove that angle A is congruent to angle B is congruent to angle C.

Answer 1

Answer :

Given : In triangle ABC, line segment AB is congruent to line segment BC is congruent to line segment CA , So

AB = BC = CA

If any triangle have all three sides equal to each other that triangle is called equilateral triangle and in equilateral triangle all three angles at 60$°$ , So

$\angle$ A = $\angle$ B = $\angle$ C = 60$°$

Therefore ,

We can say , $\angle$ A congruent to $\angle$ B congruent to $\angle$ C . ( Hence proved )