Question

In $△$ ABC, $m\angle A=\frac{2{\pi }^c}{3}$ and $m\angle B={45}^{\circ }$ . Find $m\angle C$ in both the systems.

Answer 1

$m\angle A=\frac{2{\pi }^c}{3}={120}^o$

$m\angle B={45}^o$

Therefore, $m\angle C={180}^o-{120}^o-{45}^o={15}^o=\frac{{\pi }^c}{12}$