Question

In $△ABC,m\angle A+m\angle C=m\angle B$ and $AC:AB17:15$. $IfBC=12$, find the area of $△ABC$.

Answer 1

R.E.F image

In $△ABC$

$\angle A+\angle C=\angle B$

$\frac{AC}{AB}=\frac{17}{15}$

$\frac{BC}{2}=\frac{12}{2}=6$

In $△ABC$

$\angle A+\angle C=\angle B$

$\frac{AC}{AB}=\frac{17}{15},BC=12$

$\therefore$ ar$\left(△ABC\right)$

$=\frac{1}{2}\times 15\times 8$

$\Rightarrow 60$ sq units