In △ABC , medians AD ,BE and CF are drawn on sides BC , AC and AB respectively and △ADC∼△BEC . What can you say about △ABC ?
isosceles
Given △ADC∼△BEC
ADBE=ACBC=DCEC
2EC2DC=DCEC (since D and E are mid points of BC and AC)
ECDC=DCEC⇒EC=DC
If EC = DC ⇒ AC = BC
Therefore, △ ABC is isosceles with AC = BC