In triangle ABC prove AB+BC+CA >2AB

Open in App

Solution

We know that for every triangle,
" The sum of length of two sides of triangle is always greater than third side. "

◎ AB, BC, CA are the 3 sides of a triangle.

then the,
sum of 2 sides > 3rd side

.˙. BC + CA > AB

Simply, we add 1 more AB on both sides.

.˙. AB + BC+ CA > AB + AB

AB + BC + CA > 2AB

hence proved .

Suggest Corrections

Similar questions

. O is any point in the interior of a triangle ABC. Prove that

1. AB + AC > OB + OC

2.AB + BC + CA > OA + OB + OC

3.OA + OB + OC > 1/2(AB + AC + BC)

O

+

+

>

+

+

In a triangle ABC if a point O is inside the triangle the please prove that AB + BC + CA > AO + BO + CO.

If $O$ is a point within triangle $A B C$ , show that,

A B, B C, C A

△ A B C

R, F, P

A B = B R, B C = C P, C A = A F

A (△ P E R) = 7 A (△ A B C)

Join BYJU'S Learning Program