In ABC Prove that acosB-C2-b-csinA2

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Trigonometric Ratios of Compound Angles

In ABC Prov...

Question

In $△ A B C$ Prove that $a cos (\frac{B - C}{2}) = (b + c) sin \frac{A}{2}$

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A B C

cot \frac{A}{2} - cot \frac{B}{2} = \frac{(b - a) s}{Δ}

(b + c) sin \frac{A}{2} = a cos \frac{B - C}{2}

b c {cos}^{2} \frac{A}{2} + c a {cos}^{2} \frac{B}{2} + a b {cos}^{2} \frac{C}{2} = s^{2}

(b + c) sin \frac{A}{2} = a cos \frac{B - C}{2}

a cos (\frac{B - C}{2}) = (b + c) sin \frac{A}{2}

Δ A B C

(b + c) cos (\frac{B + C}{2}) = a cos (\frac{B - C}{2})

△ A B C

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