Finding Ratio of Sides in Triangle When Angles Are Given
In triangle A...
Question
In triangle ABC, right angle at B if s-=s-b=s-c=2 then a,c are
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Solution
s-b=s-c=2 This shows both b=c=s-2 but b is opposite to angle B. Hence b is hypotenuse. For a right triangle at B b cannot be equal to c We can find a As S=(a+b+c)/2 , so 2S=a+s-2+s-2=a+2s-4 so a-4=0 and a=4